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JEE Advanced levelSingle correct optionDifficulty 3 of 3cb079

In which transformation does the atom named in brackets undergo no change in hybridisation?

A $NH X_{3} NH X_{4} X^{+}$ (nitrogen)
B $C X_{2} H X_{4} C X_{2} H X_{6}$ (carbon)
C $BF X_{3} BF X_{4} X^{-}$ (boron)
D $CO X_{2} CO X_{3} X^{2 -}$ (carbon)

Answer: A

Nitrogen is

s p^{3}

in both

NH X_{3}

and

NH X_{4} X^{+}

; the lone pair becomes a bond pair. Boron goes

s p^{2}

to

s p^{3}

, carbon goes

s p^{2}

to

s p^{3}

and carbon goes

s p

to

s p^{2}

in the other cases.

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