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JEE Main levelSingle correct optionDifficulty 2 of 3cb024

Which of the following correctly orders the O-N-O bond angles?

A $NO X_{2} X^{+} > NO X_{2} X^{-} > NO X_{2}$
B $NO X_{2} X^{-} > NO X_{2} > NO X_{2} X^{+}$
C $NO X_{2} > NO X_{2} X^{+} > NO X_{2} X^{-}$
D $NO X_{2} X^{+} > NO X_{2} > NO X_{2} X^{-}$

Answer: D

NO X_{2} X^{+}

has no lone pair on N and is linear (180 degrees).

NO X_{2}

has one unpaired electron, which repels less than a lone pair (about 134 degrees).

NO X_{2} X^{-}

has a full lone pair (about 115 degrees). Hence

NO X_{2} X^{+} > NO X_{2} > NO X_{2} X^{-}

.

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