Aspirin (2-acetoxybenzoic acid, C9H8O4) has a benzene ring carrying a -COOH group and, on the adjacent carbon, an -O-CO-CH3 group. Counting each bond's sigma component once, find the total number of sigma bonds in one molecule (give an integer).

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JEE Advanced levelNumerical answerDifficulty 3 of 3cb014

Aspirin (2-acetoxybenzoic acid, $C X_{9} H X_{8} O X_{4}$ ) has a benzene ring carrying a $- COOH$ group and, on the adjacent carbon, an $- O - CO - CH X_{3}$ group. Counting each bond's sigma component once, find the total number of sigma bonds in one molecule (give an integer).

Numerical answer type, tolerance 0.5.

Answer: 21

Aspirin has 9 + 8 + 4 = 21 atoms and one ring. The sigma framework is a connected graph, so number of sigma bonds = atoms - 1 + rings = 21 - 1 + 1 = 21. Check: ring C-C 6, ring C-H 4, ring-COOH 1, COOH 3, ring-O 1, O-C 1, C=O sigma 1, C-CH3 1, CH3 3 = 21.

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Aspirin (2-acetoxybenzoic acid, CX9​HX8​OX4​) has a benzene ring carrying a −COOH group and, on the adjacent carbon, an −O−CO−CHX3​ group. Counting each bond's sigma component once, find the total number of sigma bonds in one molecule (give an integer).

Answer: 21

More questions on Lewis structures, octet rule, formal charge

Aspirin (2-acetoxybenzoic acid, $C X_{9} H X_{8} O X_{4}$ ) has a benzene ring carrying a $- COOH$ group and, on the adjacent carbon, an $- O - CO - CH X_{3}$ group. Counting each bond's sigma component once, find the total number of sigma bonds in one molecule (give an integer).