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Lewis structures, octet rule, formal charge
NEET level
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Difficulty 1 of 3
cb004
Which of the following species contains an odd number of valence electrons?
A
\ce{N2O}
B
\ce{CO2}
C
\ce{NO2-}
D
\ce{NO}
Answer: D
Valence electrons:
NO
= 5 + 6 = 11 (odd);
N
X
2
O
= 16;
CO
X
2
= 16;
NO
X
2
X
−
= 5 + 12 + 1 = 18. Only
NO
is odd-electron.
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