Answer: A, B, C, D
The drawn compound is ethanoic anhydride. Nucleophilic acyl substitution releases carboxylate: with EtOH it gives ethyl ethanoate + ethanoic acid, with excess NH3 gives ethanamide + ammonium ethanoate. Carboxylate is a better leaving group than ethoxide, so the anhydride exceeds the ester in reactivity, and the order is RCOCl > anhydride > ester > amide. All four statements are correct.