The acid shown is treated with $Br X_{2}$ /red P and then, without isolating intermediates other than the organic product, with excess aqueous $NH X_{3}$ . Which structure is the final product?

AStructure A
BStructure B
CStructure C
DStructure D

Answer: D

The drawn compound is propanoic acid. HVZ gives 2-bromopropanoic acid; excess NH3 substitutes the alpha bromine by SN2, giving 2-aminopropanoic acid (alanine, racemic). The amide (B) would form from the acyl chloride, not from the free alpha-bromo acid; C arises with aqueous KOH; A has the amine at the wrong carbon.

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The acid shown is treated with BrX2​/red P and then, without isolating intermediates other than the organic product, with excess aqueous NHX3​. Which structure is the final product?

Answer: D

More questions on Reduction, oxidation and HVZ products of drawn carbonyls and acids

The acid shown is treated with $Br X_{2}$ /red P and then, without isolating intermediates other than the organic product, with excess aqueous $NH X_{3}$ . Which structure is the final product?