The number of different enol forms (constitutional isomers, ignoring E/Z) that the ketone shown can give is

Answer: A

The drawn compound is 2-methylpentan-3-one. Its alpha carbons are the CH2 of the ethyl group and the CH of the isopropyl group (RDKit symmetry classes: two different alpha carbons with H). Each gives one enol constitution, so 2 enols.

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