1-(4-Methylphenyl)ethanone, p-CH3-C6H4-COCH3, is treated with excess I2 and aqueous NaOH, warmed, and then acidified. The carboxylic acid formed is

JEE Main levelSingle correct optionDifficulty 2 of 3co187

1-(4-Methylphenyl)ethanone, $p - CH X_{3} - C X_{6} H X_{4} - COCH X_{3}$ , is treated with excess $I X_{2}$ and aqueous $NaOH$ , warmed, and then acidified. The carboxylic acid formed is

A methyl ketone undergoes the haloform reaction: the

COCH X_{3}

group is converted to

COO X^{-}

with loss of

CHI X_{3}

. The ring methyl group is untouched under these conditions. Acidification gives 4-methylbenzoic acid.