Formaldehyde reduces excess Tollens reagent completely to CO2 (with 4 mol of silver deposited per mole of HCHO). What mass of silver is deposited by 3.0 g of HCHO? (H 1, C 12, O 16, Ag 108)

JEE Advanced levelSingle correct optionDifficulty 3 of 3co159

Formaldehyde reduces excess Tollens reagent completely to $CO X_{2}$ (with 4 mol of silver deposited per mole of $HCHO$ ). What mass of silver is deposited by 3.0 g of $HCHO$ ? (H 1, C 12, O 16, Ag 108)

Moles of

HCHO = 3.0/30 = 0.10

. Each mole gives 4 mol Ag, so 0.40 mol Ag. Mass

= 0.40 \times 108 = 43.2