1-Cyclopentylethan-1-one is treated with Br2 in excess aqueous NaOH and then acidified. The organic acid obtained is

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1-Cyclopentylethan-1-one is treated with $Br X_{2}$ in excess aqueous $NaOH$ and then acidified. The organic acid obtained is

A methyl ketone undergoes the haloform reaction:

CH X_{3}

is lost as

CHBr X_{3}

and the carbonyl carbon becomes the carboxylate. The ring is retained, giving cyclopentanecarboxylic acid.