Answer: A, B, C
The imidazole side chain is aromatic. At pH 1 all three groups are protonated: COOH (0), α-NHX3X+ (+1) and imidazolium (+1), net +2. The pI is (6.00+9.17)/2=7.585, between 7 and 8. At pH 4 the COOH is ionised (-1), giving +1, not +2. The amino acid is histidine.