Answer: A, B, D
The compound is D-glucose: CHO plus six carbons gives an aldohexose, with stereocentres C-2 to C-5 (four). It has five OH groups, so one molecule can take up five acetyl groups. NaBH4 gives D-glucitol, which is optically active because its stereocentres are not mirror-related (checked: not meso), so the third statement is false.