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JEE Advanced levelSingle correct optionDifficulty 3 of 3bm214

A double-stranded DNA of 1000 base pairs contains 30% adenine (percentages are of all 2000 bases). Count two hydrogen bonds per A-T pair and three per G-C pair. The total number of hydrogen bonds is

  1. A2000
  2. B2400
  3. C2200
  4. D2600

Answer: B

A = 30% of 2000 = 600, so T = 600 and A-T pairs = 600. G = C = (2000 - 1200)/2 = 400, giving 400 G-C pairs. H bonds = 600 x 2 + 400 x 3 = 1200 + 1200 = 2400.
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