JEE Advanced levelOne or more correct optionsDifficulty 3 of 3bm044
Which observations about glucose are best explained by its cyclic hemiacetal structure?
AIt does not give the Schiff test.
BIt does not add NaHSO3.
CIt shows mutarotation.
DIt forms a pentaacetate.
Answer: A, B, C
The cyclic form contains very little free CHO, so Schiff and bisulphite tests fail, and ring opening and closing explains mutarotation. Pentaacetate formation only shows five OH groups, which is true for any structure.