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JEE Advanced levelSingle correct optionDifficulty 3 of 3bn214

Potassium manganate (green) in acid disproportionates to permanganate and a brown solid. Which option gives the oxidation numbers of Mn in manganate, permanganate and the brown solid $MnO X_{2}$ ?

A $+ 6, + 7, + 2$
B $+ 6, + 7, + 4$
C $+ 5, + 7, + 4$
D $+ 7, + 6, + 4$

Answer: B

MnO X_{4} X^{2 -}

: Mn = +6.

MnO X_{4} X^{-}

: Mn = +7.

MnO X_{2}

: Mn = +4. Mn(VI) goes both up (+7) and down (+4).

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