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JEE Main levelSingle correct optionDifficulty 2 of 3bn191

Which option gives both the correct name of $K X_{2} Cr X_{2} O X_{7}$ and the oxidation number of Cr in its anion?

Apotassium dichromate; Cr = +6
Bpotassium dichromate; Cr = +12
Cpotassium dichromate; Cr = +7
Dpotassium chromate; Cr = +6

Answer: A

The anion

Cr X_{2} O X_{7} X^{2 -}

is dichromate:

2 x + 7 (- 2) = - 2

gives

x = + 6

. Chromate is

CrO X_{4} X^{2 -}

.

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