JEE Advanced levelSingle correct optionDifficulty 3 of 3bn107
Arrange the average oxidation number of sulfur in increasing order: P NaX2SX2OX3 (sodium thiosulfate), Q NaX2SX4OX6 (sodium tetrathionate), R NaX2SX2OX4 (sodium dithionite), S NaX2SOX3 (sodium sulfite).
AP<Q<R<S
BQ<P<R<S
CP<R<Q<S
DS<R<Q<P
Answer: A
Average S with Na +1, O −2: P 2x=6−2=4, x=+2; Q 4x=12−2, x=+2.5; R 2x=8−2, x=+3; S x=6−2=+4. Order: +2<+2.5<+3<+4.