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JEE Advanced levelSingle correct optionDifficulty 3 of 3bn063

Arrange the average oxidation number of nitrogen in these compounds in increasing order (H $+ 1$ , O $- 2$ ): P $N X_{2} H X_{4}$ , Q $NH X_{2} OH$ , R $HN X_{3}$ , S $N X_{2} O$ .

A $Q < P < R < S$
B $P < Q < R < S$
C $P < R < Q < S$
D $S < R < Q < P$

Answer: B

N X_{2} H X_{4}

:

2 x + 4 = 0

,

x = - 2

.

NH X_{2} OH

:

x + 3 - 2 = 0

,

x = - 1

.

HN X_{3}

:

3 x + 1 = 0

,

x = - 1/3

.

N X_{2} O

:

2 x - 2 = 0

,

x = + 1

. Order:

- 2 < - 1 < - 1/3 < + 1

, i.e. P < Q < R < S.

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