JEE Advanced levelOne or more correct optionsDifficulty 3 of 3as191
The thorium series starts with X90232X2902232Th and ends with stable X82208X2822208Pb. Which statements are correct?
ASix α particles are emitted in the overall change.
BSix β− particles are emitted in the overall change.
CThe final nuclide has 126 neutrons.
DThe net decrease in the neutron number is 16.
Answer: A, C, D
α count =(232−208)/4=6 (A true). These lower Z by 12 but the net fall is 90−82=8, so β− count =12−8=4 (B false). Neutrons in Pb-208 =208−82=126 (C true). Neutrons in Th-232 =232−90=142, so the decrease is 142−126=16 (D true).