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JEE Advanced levelNumerical answerDifficulty 3 of 3as162

For an electron in a d orbital with $m_{l} = + 2$ , find the angle (in degrees, two decimals) between the orbital angular momentum vector and the $z$ axis, using $cos θ = L_{z} / L$ .

Numerical answer type, answer in degrees, tolerance 0.05.

Answer: 35.26 degrees

L = 6 ℏ

and

L_{z} = 2ℏ

.

cos θ = 2/ 6 = 0.8165

, so

θ = 35.2 6^{\circ}

.

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