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JEE Main levelSingle correct optionDifficulty 2 of 3as135

An electron sits in an orbital with $n = 4$ and two radial nodes. Its orbital angular momentum is

A $12 ℏ$
B $0$
C $2 ℏ$
D $6 ℏ$

Answer: C

n - l - 1 = 2

gives

l = 4 - 1 - 2 = 1

.

L = l (l + 1) ℏ = 2 ℏ

.

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