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JEE Advanced levelSingle correct optionDifficulty 3 of 3as091

Light from the $n = 3 \to n = 1$ transition of hydrogen falls on a metal of work function $4.0 eV$ (take $E_{1} = - 13.6 eV$ ). The maximum kinetic energy of the photoelectrons is

A $6.20 eV$
B $8.09 eV$
C $9.60 eV$
D $12.09 eV$

Answer: B

Photon energy

= 13.6 \times 8/9 = 12.09 eV

.

K E_{max} = h ν - ϕ = 12.09 - 4.0 = 8.09 eV

. The value

6.20

would use the

2 \to 1

line and

9.60

would use

13.6 - 4.0

.

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