JEE Main levelSingle correct optionDifficulty 2 of 3as077
Use RH=1.097×107m−1. The shortest wavelength in the Paschen series of hydrogen is nearest to
A820nm
B1875nm
C365nm
D91nm
Answer: A
The series limit is n=∞→3: 1/λ=RH/9, so λ=9/RH=820nm. The value 1875 nm is the longest Paschen line, 365 nm the Balmer limit and 91 nm the Lyman limit.