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Hydrogen spectrum and spectral series
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Single correct option
Difficulty 2 of 3
as073
The ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series of hydrogen is
A
27
5
B
5
27
C
4
3
D
9
4
Answer: A
Lyman:
λ
ma
x
=
4/
(
3
R
H
)
. Balmer:
λ
ma
x
=
36/
(
5
R
H
)
. The ratio is
(
4/3
)
/
(
36/5
)
=
20/108
=
5/27
.
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