Answer: A, B, C
Neutrons = 127 - 53 = 74; electrons = 53 + 1 = 54, the same as Xe (Z = 54), so it is isoelectronic with Xe. Xe-128 has 128 - 54 = 74 neutrons, equal to 74, so they are isotones. Xe-127 has a different atomic number but the same mass number, so it is an isobar, not an isotope.