When light of wavelength $200\mathrm{nm}$ falls on a metal, the maximum kinetic energy of the photoelectrons is 2 times that obtained with light of wavelength $300\mathrm{nm}$. Find the work function of the metal in eV, to two decimals. Use $h=6.626\times 10^{-34}\mathrm{J}\mathrm{s}$, $c=3.0\times 10^8\mathrm{m}{\mathrm{s}}^{-1}$, $1\mathrm{eV}=1.6\times 10^{-19}\mathrm{J}$.

Numerical answer type, answer in eV, tolerance 0.03.