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JEE Main levelSingle correct optionDifficulty 2 of 3as017

The energy of a photon of wavelength is closest to (use , , )

  1. A1.25 eV
  2. B4.0 eV
  3. C0.5 eV
  4. D2.0 eV

Answer: D

E = hc/ = (6.626e-34)(3.0e8)/(620e-9) = 3.206e-19 J. Dividing by 1.6e-19 J/eV gives 2.00 eV, about 2.0 eV.
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