Answer: A
No reaction with Na shows X is an ether. A tertiary iodide and methanol come from SN1 cleavage of a tert-alkyl methyl ether. With C5H12O, (CHX3)X3C−O−CHX3 gives (CHX3)X3C−I and CHX3OH; the other isomers cleave by SN2 and do not give a tertiary iodide.