Arrange the alcohols I = butan-2-ol, II = 2-methylpropan-2-ol, III = butan-1-ol in decreasing order of rate of reaction with $ZnCl X_{2}$ /conc. $HCl$ .

AI $>$ II $>$ III
BII $>$ I $>$ III
CIII $>$ I $>$ II
DII $>$ III $>$ I

Answer: B

The rate depends on the stability of the carbocation formed: tertiary > secondary > primary. II is tertiary, I is secondary and III is primary, so the order is II > I > III.

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Arrange the alcohols I = butan-2-ol, II = 2-methylpropan-2-ol, III = butan-1-ol in decreasing order of rate of reaction with ZnClX2​/conc. HCl.

Answer: B

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Arrange the alcohols I = butan-2-ol, II = 2-methylpropan-2-ol, III = butan-1-ol in decreasing order of rate of reaction with $ZnCl X_{2}$ /conc. $HCl$ .