Answer: D
Step 1 gives 2-methylbutan-2-ol, and dehydration (Saytzeff) gives the trisubstituted alkene 2-methylbut-2-ene, (CHX3)X2C=CH−CHX3. Hydroboration places boron on the less substituted alkene carbon (the =CHX− carbon), so OH ends up on C-2 of the butane chain bearing a methyl at C-3: 3-methylbutan-2-ol.