Hydroboration-oxidation (BH3 in THF, then H2O2/NaOH) of propene gives mainly

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NEET levelSingle correct optionDifficulty 1 of 3ap002

Hydroboration-oxidation ( $BH X_{3}$ in THF, then $H X_{2} O X_{2}$ / $NaOH$ ) of propene gives mainly

Apropan-2-ol
Bpropan-1-ol
Cpropanal
Dpropanone

Answer: B

Hydroboration-oxidation is anti-Markovnikov: boron attaches to the terminal carbon, so oxidation gives the primary alcohol propan-1-ol. Propan-2-ol is the Markovnikov hydration product.

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Hydroboration-oxidation (BHX3​ in THF, then HX2​OX2​/NaOH) of propene gives mainly

Answer: B

More questions on Preparation of alcohols including from carbonyls and Grignard

Hydroboration-oxidation ( $BH X_{3}$ in THF, then $H X_{2} O X_{2}$ / $NaOH$ ) of propene gives mainly